Question

-2(y-4)-(3y-2)=-2-(6y-2)

Answer 1

First solve what is in parenthesis

Answer 2

-2y-8-3y-2=-2-(6y-2)

Answer 3

actually it is -2y+8-3y+2 = -2-6y+2

Answer 4

Now combine like terms

Answer 5

1y+6 = -2-(6y-2)?

Answer 6

-2y -3y = -5y
8 + 2 = 10
so you have
-5y+10 = -2 +y +2
now do the same on the other side

Answer 7

sorry I meant
-5y +10 = -2 -6y +2

Answer 8

I do not see the +10 when -2y+(-3y)+8-2

Answer 9

lets start you have
-2(y-4)-(3y-2) = -2-(6y-2)
-2y+8-3y+4 = -2-6y+2

Answer 10

(-2)(y)=-2y
(-2)(-4) = positive 8
(-)(3y) = -3y
(-)(-2) = positive 2
can you see it ??

Answer 11

sorry it is -2y+8-3y+2 = -2-6y+2

Answer 12

now you combine like terms -2y-3y = -5y and 8+2 = 10

Answer 13

now you have -5y+10 = -6y (because -2+2=0)

Answer 14

Hope you can take it from there, I have to go

Answer 15

Thank you for your help