Question

a container contains 50 green tokens, 20 blue, and 3 red. 2 tokens are pulled randomely. Compute P(FIE). E-you select a non-blue first. F-the second is non-blue

Answer 1

Can anyone help me?

Answer 2

without replacement?

Answer 3

yes

Answer 4

Are you able to help me?

Answer 5

is this conditional prob...prob of F given E

Answer 6

I am not really sure..

Answer 7

\(P(F|E)\)

so E has happened so a non-blue has been selected

Answer 8

I am finding P(FIE) =?

Answer 9

so there are now only 72 tokens remaining....how many anre non-blue?

Answer 10

*how many are non-blue?

Answer 11

still 20
?

Answer 12

originally there were 53 non-blue

Answer 13

so then there are still 53 non-blue

Answer 14

no...event E has happened...a non-blue has been selected.

Answer 15

so 52

Answer 16

correct...so what is the probability?

Answer 17

52/72?

Answer 18

correct

Answer 19

and that is the answer?

Answer 20

that was simple!