The sum of two consecutive even integers is 226. What is the larger integer?

Question

whpalmer4 · Answer

One even integer can be written as 2n, where n is an integer.  The next consecutive even integer after 2n would be 2n + 2, right?  So 2n + (2n+2) = 226.  Find n, then use it to find the value of 2n+2.

jenniferjuice · Answer

ummm so do i ....

whpalmer4 · Answer

you solve 2n + (2n+2) = 226...

whpalmer4 · Answer

$$2n+(2n+2)=226$$$$4n+2=226$$your turn...

jenniferjuice · Answer

alright let me write this down

jenniferjuice · Answer

and try to solve it

anonymous · Answer

i have an idea, lets guess and check

whpalmer4 · Answer

operators are standing by to check your answer :-)

anonymous · Answer

$110+112=222$ nope

anonymous · Answer

bet i can guess it on the second try though...

whpalmer4 · Answer

or even on the first, if you tried the two numbers surrounding half of 226 :-)

jenniferjuice · Answer

would i add 2n +2n? first?

anonymous · Answer

i am not that smart
but if you order now you will get two 
plus the can opener

anonymous · Answer

@jenniferjuice  you are smarter than that
no need to solve a silly equation
just guess and check

whpalmer4 · Answer

$$4n + 2 = 226$$subtract 2 from both sides$$4n=224$$$$n=56$$so the big number was 2n+2 = 2(56)+2 =

jenniferjuice · Answer

oh i thought about that as well but i wasn't quite sure

anonymous · Answer

like i said, since $110+112$ is too small, try a slightly larger one

jenniferjuice · Answer

@whpalmer4 |dw:1371519089344:dw|