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implicit derivate of y=sen(xy) ??
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dy/dx=cos(xy)d/dx(xy) dy/dx=cos(xy)*(y+xdy/dx) dy/dx=ycos(xy)+dy/dx(xcos(xy)) dy/dx(1-xcos(xy)=ycos(xy) dy/dx=ycos(xy)/1-xcos(xy)
@parth its sin
Thanks you very much!
dy/dx = d/dx ( sinxy) = cosxy d/dx(xy) = cosxy [ y + x(dy/dx)] dy/dx = [ycosxy]/[1- xcosxy]
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