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Given that IJKL is a square, find x & y. (PLEASE ANY HELP:)
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a) x=2, y=8 b) x=8, y=2 c) x=43, y=2 d) x=2, y=43
since all the sides a equal in a square, 2x+4=3y+8=5y+4. first, find the value of y. 3y+8=5y+4=>2y=4=>y=2 substitute the value of y in 2x+4=3y+8 =>2x+4=3(2)+8 =>2x+4=14=>2x=10=> x=5.
so my answer is b or c??
x=5 and y=2.
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x=5 isnt one of my options. i think theres a mistake somewhere.
a) x=2, y=8 b) x=8, y=2 c) x=43, y=2 d) x=2, y=43 Here are my options.
And ive checked my work twice. No numbers are out of order or misplaced.
hint :- angle in a square is 90 degrees
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2x + 4 = 90 solve x
2x+4= 90 ?
yes
2x=86
x=43
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