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change the quadratic function to standard form y=3(x+2)(x-5)
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you have to multiply the monoms x=2 and x-5 let see: \[y=3(x*x-5*x+2*x+2*(-5))=3(x^2-5x+2x-10)=3(x^2-3x-10)=3x^2-9x-30\]
sorry missed the final though: \[3x^2-9x-30\]
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