Question

Solve for x.

3(2x - 3) + 4(2 - x) = 0

A. 1/2
B. 17/10
C. -17/2

Answer 1

First, expand out your polynomial using the distributive property of multiplication.

\[3(2x-3)+4(2-x) = 0\]\[3*2x-3*3 + 4*2 -4*x = 0\]Now collect like terms and solve for \(x\).

Answer 2

Reorder the terms:
3(-3 + 2x) + 4(2 + -1x) = 0
(-3 * 3 + 2x * 3) + 4(2 + -1x) = 0
(-9 + 6x) + 4(2 + -1x) = 0
-9 + 6x + (2 * 4 + -1x * 4) = 0
-9 + 6x + (8 + -4x) = 0

Reorder the terms:
-9 + 8 + 6x + -4x = 0

Combine like terms: -9 + 8 = -1
-1 + 6x + -4x = 0

Combine like terms: 6x + -4x = 2x
-1 + 2x = 0

Solving
-1 + 2x = 0

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '1' to each side of the equation.
-1 + 1 + 2x = 0 + 1

Combine like terms: -1 + 1 = 0
0 + 2x = 0 + 1
2x = 0 + 1

Combine like terms: 0 + 1 = 1
2x = 1

Divide each side by '2'.
x = 0.5

Simplifying
x = 0.5