If the length of a large banner is 4x + 5 and the width is half as long, what is the area?
A. 6x² + 20x + 12.5
B. 8x² + 17x + 12.5
C. 8x² + 20x + 12.5
D. 8x² + 22x + 12.5

Question

If the length of a large banner is 4x + 5 and the width is half as long, what is the area?
	A.	6x² + 20x + 12.5
	B.	8x² + 17x + 12.5 
	C.	8x² + 20x + 12.5 
	D.	8x² + 22x + 12.5

anonymous · Answer

to find the area of a banner (which is usually in the form pf a rectangle)
$$\Large A=l \times w$$

anonymous · Answer

you were given the length to be 4x+5 and you were told the width as half as long 
so the area of the banner would be
$$\Large A=(4x+5)(\frac{ 1 }{ 2 }(4x+5))$$

anonymous · Answer

do you understand what i have done?

anonymous · Answer

yes

anonymous · Answer

can you continue from there?