Question

If the length of a large banner is 4x + 5 and the width is half as long, what is the area?
A. 6x² + 20x + 12.5
B. 8x² + 17x + 12.5
C. 8x² + 20x + 12.5
D. 8x² + 22x + 12.5

Answer 1

to find the area of a banner (which is usually in the form pf a rectangle)
\[\Large A=l \times w\]

Answer 2

you were given the length to be 4x+5 and you were told the width as half as long
so the area of the banner would be
\[\Large A=(4x+5)(\frac{ 1 }{ 2 }(4x+5))\]

Answer 3

do you understand what i have done?

Answer 4

yes

Answer 5

can you continue from there?