Question

What is the 41st term of the arithmetic sequence where a1 = 16 and a15 = -40 ?

Answer 1

nth term of an AP = a1 + (n - 1)d

Answer 2

Any general n-th term of an A.P. is ,
a_n = a_1 + (n-1)d

Find 'd' and 'n' is known...

Answer 3

plug in a1 = 16, n = 15 15th term -41 to get value of common difference d

Answer 4

41st term = 16 + (41 - 1)d

Answer 5

56(d)

Answer 6

no 16 + 40d

Answer 7

but you need to find d

Answer 8

sorry i had that wrong
the 15th term is -40 so:

-40 = 16 + (13 - 1) d

now can you solve this for d?

Answer 9

oohh whats wrong with me

n = 15

so its

-40 = 16 + (15 - 1) d

Answer 10

can u do that?