Question

find the vertex form of the following equation by completing the square. y=3x^2+6x+8
A.y=(x+4)^2
B.y=3(x+2)^2+4
C. y=3(x+1)^2+5
D. y=(x+3)^2+5

Answer 1

why not just roll a dice?

Answer 2

\[3x^{2} +6x = 3(x^{2}+2x) = 3(x^{2}+2x+1) -3 = 3(x+1)^{2} -3\]