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8x/3 - x/2 = -13
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multiply 6 by both sides, 16x-3x=-78, then 13x=-78, x=-6
2(8x)-3(x)/6=-13
1. Add 13 to both sides 2. Add x/2 to both sides 3. Rewrite 13 as 39/3 4. Combine 8x/3 with 39/3 5. Cross mulitply 6. Isolate x: \[\frac{8x}{3} + 13 = \frac{x}{2}\] \[\frac{8x}{3} + \frac{39}{3} = \frac{x}{2}\] \[\frac{8x + 39}{3} = \frac{x}{2}\] \[2(8x + 39) = 3x\] \[16x + 78 = 3x\] \[(16 - 3)x = -78\] Finish solving from there
Thanks a ton. Thanks to everyone.
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