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find discontinuity? if removable, define a new function that removes the discontinuity.. f(x)= x lnx^2 i get the topic just forgot ln. refresh my memory?
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\(\ln y=x\Leftrightarrow y=e^x\)
Since \(e^x>0\) we can tell \(\ln y\) is undefined for \(y=0\)
that's right i got you, thanks!
no problem! that means our function is undefined at \(x=0\), hence there's our 'discontinuity'. To determine whether it's 'removable', see if our left and right limits match up... :-)
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