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Find the surface area of a pyramid with area of the base 20, slant height 7, and perimeter of the base 30.
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S = B + (1/2)Pl, where B is the base area, P is the perimeter of the base, and l is the slant height. Given that the base area is 20, the slant height is 7, and the perimeter of the base is 30, we see that: S = 20 + (1/2)(30)(7) = 125 units^2.
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