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OpenStudy (anonymous):
What is the solution set for |x – 2|– 1 > 2?
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OpenStudy (ivettef365):
for the absolute value you need to find 2 solutions (-) and (+)
so you have
x-2>3 and x-2<-1
OpenStudy (anonymous):
What is the solution set for |x – 2|– 1 > 2?
x > 5 or x < –1
x < 5 or x > –1
x > –5 or x < 1
x < 5 or x > –5
OpenStudy (ivettef365):
this is how you do this problem:
{x-2}-1>2
+1 +1
------------
{x-2} > 3, then you have x-2>3 solve for x
OpenStudy (ivettef365):
the second equation would be:
{x-2}-1<-2 (switch both signe the + to - and the > to <
OpenStudy (anonymous):
I got c
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OpenStudy (ivettef365):
then you have
{x-2} -1 < -2
+1 +1
------------
x-2 <-1 solve for x
OpenStudy (anonymous):
im not 100% sure
OpenStudy (anonymous):
no wait its either the first answer or second one
OpenStudy (ivettef365):
no it is actually x>5 or x<-1
OpenStudy (ivettef365):
first you convert as follows:
x - 2 > 3 or x - 2 < -3
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OpenStudy (ivettef365):
then you have
x - 2 > 3 x - 2 < -3
+2 +2 and +2 +2
---------- -----------
x > 5 x < -1
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