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If Cos θ = 2 √ 10 / 7 calculate the value of Sin θ.
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Draw a triangle
I draw a rt triangle, I am not sure of the procedure to solve
Show me your triangle
Use a^2+b^2=c^2
Yes, I tried Pythagoras as 2 sqrt(10) + b^2 = 7^2
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\[(2\sqrt{10})^2+b^2=7^2\]
so that gives you: 4(10)+b^2=49 subtract 40: b^2=9
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