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For the geometric sequence -8,16,-32.....find a5
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start by finding \(r\)
how do i do thatt
divide any 'next element' with 'present element'
\(r = \frac{16}{-8}\)
is -2
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than -32/16?
Yes, \(r = -2\)
Now use the \(nth\) term formula to find \(a_5\)
the 9th term? i only see 3 terms
\(\large a_n = ar^{n-1}\)
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plugin n = 5, r = -2
\(\large a_5 = -8 (-2)^{5-1}\)
simplify
64?
\(\large a_5 = -8 (-2)^{4}\) \(\large \ \ \ = -8 \times 16\)
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lol oh -128
Yes
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