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OpenStudy (anonymous):
solve for x: 9^(2x+1) = 27^(x-2)
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OpenStudy (anonymous):
\[9^{2x+1} = 27^{x-2}\]
ganeshie8 (ganeshie8):
hint : powers of 3
OpenStudy (anonymous):
yes so what next?
OpenStudy (john_es):
\[9^{2x+1}=27^{x-2}\Rightarrow (3^2)^{2x+1}=(3^3)^{x-2}\Rightarrow 3^{4x+2}=3^{3x-6}\] \[\Rightarrow 4x+2=3x-6\] And solve.
OpenStudy (anonymous):
ok thanks mate
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