Question

solve for x: 4^x - 3*2^(x+1) = 16

Answer 1

\[4^{x} - 3 * 2^{x+1} =16\]

Answer 2

Hint: take log on both sides

Answer 3

can you solve for me. i guarantee a medal

Answer 4

\[\log(4^{x}) -3.\log(2^{x+1}) = \log(16)\]
\[x.\log4 - 3 (x+1) \log2 = \log 16\]

Answer 5

log functin won't work here.