Ask your own question, for FREE!
Algebra 14 Online
OpenStudy (anonymous):

One month, a music site observed that 60% of the people who downloaded songs from its site downloaded Q Sam's latest single. The equation below represents this information, where x represents the total number of people who downloaded songs from the site that month. x = 0.6x + 384 How many people who downloaded songs from the site that month downloaded Q Sam's latest single?

OpenStudy (anonymous):

Where do I start?

OpenStudy (dan815):

nvm i guess this works too

OpenStudy (dan815):

solve for x

OpenStudy (anonymous):

What exactly do I do?

OpenStudy (dan815):

solve for x by getting all the terms with x on 1 side

OpenStudy (dan815):

ur equation looks weird tho.. are u sure thats how it really is

OpenStudy (dan815):

x = 0.6x + 384 if this ur equation and i set x = 0 then 0=384.. doesnt make sense

OpenStudy (anonymous):

so it would turn into a negative X right? and yeah thats what it says right here on the website!

OpenStudy (anonymous):

seems a little odd given the words that you have \(x\) on both sides of the equal sign, but no matter, you can go ahead a solve anyway

OpenStudy (anonymous):

\[x = 0.6x + 38\\ .4x=384\\ x=384\div .4=3840\div 4=960\]

OpenStudy (anonymous):

Where did you get the .4? sorry for asking lol I understand this is a very awkward problem lol

OpenStudy (anonymous):

you start with \[x=.6x+384\] to get \(x\) on one side of the equal sign, subtract \(.6x\) from both sides \[x=.6x+384\\x-.6x=684\\.4x=384\]

OpenStudy (anonymous):

typo there, but you get the idea right?

OpenStudy (anonymous):

if the decimal annoys you you can always multiply both sides by 10 and get \[10x=6x+3840\\ 4x=6840\\x=3840\div 4\]

OpenStudy (anonymous):

I don't understand why they did not have this as a example iin the lessons xD But now I do get it...

OpenStudy (anonymous):

maybe they had a problem like "solve for \(x\), \( 2x=6x+5\) " but maybe not

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!