Question

Help asap please! c:
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3).

Answer 1

y = 2x + 2
for a perpendicular line, the slope is the negative reciprocal. So the slope is the negative reciprocal of 2 which is - 1/2.

y = mx + b ....using slope -1/2 and points (6,3)
3 = -1/2(6) + b
3 = - 3 + b
3 + 3 = b
6 = b

your equation is : y = - 1/2x + 6 (slope intercept form)
or if you need it in standard form : Ax + By = C, then it is ...
y = - 1/2x + 6 (multiply everything by 2)
2y = - x + 12
x + 2y = 12 <--standard form

Answer 2

Thank You! (:

Answer 3

not a problem...glad I could help :)