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what is the factor of 64x3-8 then solve it?
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(64x^3) -8 = 4^3*x^3-2^3 = (4x)^3 - 2^3 I think you have a formula for the rest?
hint: a^3-b^3=(a-b)(a^2+ab+b^2)
can you solve the given factor?
I have showed you how you have (4x)^3-2^3 and a^3-b^3 = (a-b)(a^2+ab+b^2) so let a = 4x and b= 2 what do you have?
can you give me on how to check my answer if its right?
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