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Multiply (2-3a)^3
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\[(2-3a)^{3}\]
\[(2-3a)(2-3a)(2-3a)\]
bf \[\bf (a+b)^3=a^3+2a^2b+ab^2+a^2b+2ab^2+b^3\]
@cahayes9498
\[=(2-3a)(2-3a)^2\\=(2-3a)\big(2(2-3a)-3a(2-3a)\big)\\=(2-3a)(4-6a-6a+9a^2)\]
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@genius12 doing that I end up getting\[(2-3a)^{3}=3-9a+9a ^{2}=2\times3-2\times9a+2\times9a ^{2}-3a \times4+4a \times16a-4a \times16a ^{2}\] then I get stuck
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yes
\[(3-a)^{3}\]
|dw:1371789345487:dw|
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