What is the center and radius of the circle with the equation x2 + y2 – 10x – 12y + 36 = 0 ?

Question

anonymous · Answer

x2  – 10x + y2– 12y + 36 = 0 
x2-10x+25+y2-12+36=-36+36+25
(x-5)^2+(y-6)^=25
were do i go from here ?

anonymous · Answer

gd!

this is in the form of standard equation of a circle.

(x-h)^2 + (y-k)^2 = (r)^2

compare your equation with this one.
get the value of (h,k)  which is co-ordinates of the centre of circle and r = radius/

dan815 · Answer

yes put it in that form it will be fun >_>

anonymous · Answer

soo Center: (5, 6); how do i find the radius ?

dan815 · Answer

complete the squarea and ull know the constant u will have left over

dan815 · Answer

show ur work

anonymous · Answer

in your equation =25 is written

=(5)^2

that means the radius = 5

anonymous · Answer

thankyou very much ! (:

anonymous · Answer

welcome!

dan815 · Answer

oh u already solved it up there good job