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Find Third Taylor Polynomial at x=0 for the function f(x)= 3sqrt(2x+1)
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what is the formula for the taylor expansion of a function around x=a ?
so where are you stuck then?
im unsure how to start it.
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you need up until the nth derivative term. In your case n=3, so you need\[f(x)\approx f(0)+\frac{f'(0)}{1!}+\frac{f''(0)}{2!}+\frac{f'''(0)}{3!}\]
so you might want to start by getting the values f(0), f'(0), f''(0), and f''(0)
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