Question

Find all natural numbers n>1 such that n^2 does not divide (n-2)!.

Answer 1

@wio

Answer 2

Hmmmm

Answer 3

@ParthKohli Help me brother

Answer 4

Maybe there are a handful of numbers, and you have to prove why the other ones don't work.

Answer 5

consider even and odd case. That could narrow things down.

Answer 6

\[(n-2)!\] Is going to be even, because it is equal to \[
(n-2)(n-3)(n-4)...(3)(2)(1)
\]The two makes it all even.

Answer 7

Though I don't know if this info helps at all.