Question

which is the exact value of the expression 6 sqrt(x)-sqrt(4v^2)-sqrt(36v)+sqrt(v^2)

Answer 1

$$\sqrt{4v^2}=2v,\sqrt{v^2}=v,\sqrt{36v}=6\sqrt{v}$$

Answer 2

So we have \(6\sqrt{x}-2v-6\sqrt{v}+v=-v-6\sqrt{v}+6\sqrt{x}\)

Answer 3

this are my possible answers
3v
\[v \sqrt{v}\]
-v
\[6v ^{2}\]

Answer 4

@msellier that's not meant to be an \(x\), then, is it? :-)

Answer 5

If you meant \(6\sqrt{v}-\sqrt{4v^2}-\sqrt{36v}+\sqrt{v^2}=6\sqrt{v}-2v-6\sqrt{v}+v=-v\)

Answer 6

yes sorry my bad i meant a v
thx for your help now i got it thank you

Answer 7

np!

Answer 8

could you help me with another on please