Question

What is the equation of the line passing through (2, -3) and parallel to the line y = -6x - 1 in standard form?

Answer 1

a) 6x + y = 9
b) 6x - y = -9
c) x + 6y = 9
d) x - 6y = -9

Answer 2

the equation of line will b\[y-y _{1}=m(x-x _{1})\]

Answer 3

u hv slope of ur given line is\[m=-6\]

Answer 4

so any line which is parallel to ur given line hv slope\[m=-6\]

Answer 5

so its y-(-3)=-6(x-2)

Answer 6

so the equation of ur required line will b\[y-(-3)=-6(x-2)\]

Answer 7

ya

Answer 8

i got b. 6x-y=-9

Answer 9

am i correct?

Answer 10

formula =>
\[(y-y1)=m(x-x1)\]
use this formula
where m=-6 and (x1 , y1)=(2,-3)
u will get the equation

Answer 11

may i know the name of ur country @danny562

Answer 12

ans is option a ....

Answer 13

wait is the answer a or b?

Answer 14

a

Answer 15

6x+y=9

Answer 16

s.... solve by substituting ...

Answer 17

noo ....y+6x=9

Answer 18

\[y-(-3)=-6(x-2) \]
\[y+3-6x+12\]
\[y+6x=12-3\]
\[y+6x=9\]

Answer 19

in options its 6x+y=9 same as y+6x=9