Question

What is the equation of the line passing through (8, –6) and perpendicular to the line y = x – 2 in slope-intercept form?
a. y = –x + 2
b. y = x + 2
c. y = –x – 2
d. y = x – 2

Answer 1

@Noura11 can you help?

Answer 2

@shamim how about you?

Answer 3

f9

Answer 4

ur given line is\[y=x-2\]

Answer 5

An equation of line is :
\[y=mx+b\]
Since the line is perpendicular to the line y = x – 2 then :
\[m\times 1=-1\]
and so :
\[m=-1\]
to find be, since (8,-6) is from the line :
\[-6=-1\times 8+b\]
so :
\[b=-6+8=-2\]
So the equation of the line is :
\[y=-x-2\]

Answer 6

Damn, that was amazing.

Answer 7

so the slope of ur given line is\[m _{1}=1\]

Answer 8

1 problem. that answer wasnt one of the choices

Answer 9

@Noura11

Answer 10

What it is ?

Answer 11

lol pellet, i was confusing 2 different problems, you are both correct. best answer goes to @Noura11 for the most correct work shown.