as a part of an abstract sculpture, an artist must completely cover a cylinder with one layer of gold foil. The cylinder is 2.44 dm high and the basses have radius 22.52 cm. The cost of the gold is $281 per square foot. How much will it cost to wrap the cylinder with the necessary amount of foil?

Question

aaronq · Answer

calculate the surface area of the cylinder.. 

SA = 2pi(r^2) + 2pi(r)

lol why would they give you the gold amount in ft? are they 'murican or something..

convert to ft..  1 ft^2 = 0.093 m^2

or convert the price to meters