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(sinx-cosx+1)/(sinx+cosx-1)=sinx+1/cosx
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its a little confusing, can you use more brackets ?
plz help me to solve me this question (sinx-cosx+1)/sinx+cosx-1)=sinx+1/cosx
@shivamsharan are you aware of the double angles?
no
divide numerator and denominator by cosx..!! and try to proceed..
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bt how plz u show me once i didn't understood please pleease show me once
sin(2x)=2(sinx)(cosx), and cos(2x)=1-2sin^(2)x=2cos^(2)x-1.
i didn't get it plz
well the expression wud be reduced to(tanx-1+secx)/tanx+1-secx).... then use sec^2x-tan^2x=1..then the things will automatically simplify..:)
how can u show me once by doin it please
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u can't solve it
no actually it wud become a little bit long,,actually very long...
k
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