Question

Find the quotient of 3x^3 + 9x^2 -6x / -3x

Answer 1

Is the quotient :
\[\frac{3x^3+9x^2-6x}{-3x}?\]

Answer 2

Yes

Answer 3

OK !
Use the rule :
\[\frac{a+b+c}{d}=\frac ad+\frac bd+\frac cd\]

Answer 4

Okay so 3/-3 9/-3 6/-3 ? I honestly have no idea...

Answer 5

Listen to me !
It is very simple :
\[\frac{3x^3+9x^2−6x}{−3x}=\frac{3x^3}{-3x}+\frac{9x^2}{-3x}+\frac{-6x}{-3x}
\\~~~~~~~~~~~~~~~~~~~~~~~~=-x^2-3x+2
\]