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inverse of a function: g(x)=x+2/x-3
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is the answer 2/3???
@terenzreignz , xDDD
\[\LARGE y=\frac{x+2}{x-3}\] solve for x?
@derek11111 the way to do this, is replace f(x) with y, as DLS stated and then switch x and y. \[\Large x = \frac{y+2}{y - 3}\]
Now solve for y.
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same thing :o
yeah, mine's prettier XD OR not...
|dw:1372134826137:dw|
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