Question

Solve the following problem for the roots by using the quadratic formula.

2(6 - x) = x(x + 5)

Answer 1

2(6 - x) = x(x + 5)
i.e. 12 - 2x = x^2 +5
i.e. x^2 +5 +2x -12=0
i.e. x^2 +2x -7=0
comparing it with general eq of quadratic eq i.e ax^2 +bx +c = 0, we get
a= 1, b= 2, c= -7
Quadratic eq formula is given as:
x=(-b±√(b^2-4ac))/2a
x=(-2±√{2^2-4*1*(-7)}/2*1
x=(-2±√{4+28}/2
x=(-2±√{32}/2
x=(-2±4√{2}/2
x=(-1±2√{2} which are the required roots of x.