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Find the sum of the geometric series
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so, a1... a10, you have 10 terms
n = 10
since you knw a1, and r, you can use the geometric series sum formula directly ?
\(\large S_n = a_1(\frac{1-r^n}{1-r})\)
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just plug and chug
i got 1/-1
how ?
im gona do it again
Ok :) \(\large S_n = a_1(\frac{1-r^n}{1-r}) \) \(\large S_n = -1(\frac{1-(-2)^{10}}{1--2}) \) \(\large S_n = -1(\frac{1- 2^{10}}{1+2}) \) = ?
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341?
Yes !
gw! :)
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