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find a7 for the geometric series with
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\(a_n = a_1 r^{n-1}\)
\(a_7 = a_1 r^{7-1}\)
plugin the given \(a_1 \) and \(r\) values
okay. is that the formula i use
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Yes
-24?
try again
where do i put the 86?
\(a_7 = 2 (-2)^{7-1} \)
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we dont use 86 for this
128
Yes ! \(a_7 = 128\)
i now have to find a8 do i use the same formula?
they gave me r s8 and a1
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yes same formula
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