Question

y=x^2-4x-12 factored is (x-6) (x+2), how do i determine vertex?

Answer 1

vertex form is y = a(x-h)^2 +k where vertex is (h,k)

Answer 2

so how do i put this equation into vertex form?

Answer 3

i just dont see where the h and k come in from

Answer 4

(x^2-h)^2+k?

Answer 5

'h' and 'k' are just place holders. They, like 'a', can be anything.

Answer 6

so how do i find the vertex now? what do i have to put in for h and k