Question

find critical pts. of sin^3(x^3)

Answer 1

Find the derivative. Set the derivative equal to zero. Solve for x

Answer 2

ugh. connection.

Answer 3

hang on.

Answer 4

\[\sin^3(x^3)\]
let u equal x^3
\[\sin^3(u)\]
\[\frac{ d }{ du } = \sin^3(u) = 3\sin^2(u)*\cos(u)\]
Chain rule says
\[f'(g(x))*g'(x); g(x)= x^3; f(x)= \sin^3(u)\]
\[\frac{ d }{ dx }\sin^3(x^3) = 9x^2\sin^2(x^3)\cos(x^3)\]

Answer 5

Oh, I thought it was just asking for the critical points

Answer 6

Yeah, finding the maximums and minimums would be terrible, but we know what the critical points are.

Answer 7

maxima and minima... >.<

Answer 8

?