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Find a8 for the geometric series with
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\[\large a_{8}= (4)(2)^{8-1}\]
do you understand why...
yeah its the formula sn=a1(1-r)/(1-r)
what are all these Ss and As
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No Geometric series is \[\large \sum_{n=1}^{8}4(2)^{8-1}\]
oohhhh
Geometric Series\[\large \sum_{n=1}^{n}a_{1}r^{n-1}\]
i got 4096
you know what would be helpful? It'd be a good idea to make a flashcard with all the types of series on it. You could refer back to them when applying diference series and sequence tests .
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different*
That's what I did when I was learning Series and Sequences.
\[\large a_{8} = 4\times 2^7= 512.\]
aha oh
How did you get 4096?
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so confusing..
what is the difference between S8 and A8
S means the sum of the geometric series, a8 means the 8th number in the series.
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