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The line that is the perpendicular bisector of the segment whose endpoints are R(-1, 6) and S(5, 5)
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|dw:1372136573158:dw|
let the mid point is T(x,y)
so\[x=\frac{ -1+5 }{ 2 }=2\]
and\[y=\frac{ 6+5 }{ 2 }=\frac{ 11 }{ 2 }\]
did u get it
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i need it in standard from
i can get all that i just need help getting it in standard form
now the slope of ur given line RS\[m _{1}=\frac{ 6-5 }{ -1-5 }=-\frac{ 1 }{ 6 }\]
ok
\[y-\frac{ 11 }{ 2 }=6(x-2)\]
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is it wt u want
u can also write \[12x-2y=13\]
m i wrong
no your right thank you.
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