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(x + 3)/4) * 3(x -6)/ 3(x + 3)
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cross cancel factors
(x-6)/4
\[\frac{ (x+3) }{ 4}*\frac{ 3(x-6) }{ 3(x+3) }\]
(\[\frac{ (x-6) }{ 4 }\]
can you show me how you get it @cebroski
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cross out the threes
cross out the (x + 3)'s
combine into one fraction
\[\large\frac{\cancel{(x+3)}}{4} \times \frac{\cancel{3}(x-6)}{\cancel{3(x+3)}}\]\[\large = \frac{x-6}{4}\]
magick
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Okay Thanks everyone
jhanny to the rescue. nice cross cancelling!!!
ty :)
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