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OpenStudy (anonymous):
Would the current that is flowing through R1 be 2mA? Please explain how. http://user-content.enotes.com/37e352ae8dd206a9ba6b081e5981f4c77aa1f87b.jpg
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OpenStudy (anonymous):
2mA. Apply Ohm's law across R1. Potential difference across R1 =10V as battery is directly connected across it. 10=IR R=2*10^-3 ohms So I=2mA
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