Question

how do you do this
-squareroot m^4 n^7

Answer 1

\[-(m^2n^7)^{1/2}\]

Answer 2

\[-(m^2n^7)^{1/2}\]
\[=-(m^{2*{1/2}}n^{7*{1/2}})\]
\[=-(m^{1}n^{7/2})\]

Answer 3

would the answer be -m^2 n^2 to the square root of n

Answer 4

oh umm yes that shud be m^4*1/2

Answer 5

so -(m^2*m^7/2)