Question

Find the slope-intercept equation of the line with the following properties parallel to the 5x+2y=1; containing the point (-5,4).

Answer 1

to find the slope, lets isolate y
5x + 2y = 1
2y = - 5x + 1
y = -5/2x + 1/2
here the slope is -5/2, and if you are looking for a parallel line, the slope will be the same. So the slope is - 5/2
Now we will put our info in y = mx + b
using slope -5/2 and points (-5,4)
y = mx + b
4 = -5/2(-5) + b
4 = 25/2 + b
4 - 25/2 = b
8/2 - 25/2 = b
- 17/2 = b

so your equation is y = - 5/2x - 17/2