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OpenStudy (anonymous):
solve and check
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OpenStudy (anonymous):
ganeshie8 (ganeshie8):
cross multiply
OpenStudy (anonymous):
then what? i dont know what my common denominator would be
OpenStudy (anonymous):
oh wait, x= 5?
ganeshie8 (ganeshie8):
try again
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OpenStudy (anonymous):
ok
OpenStudy (anonymous):
x=3
ganeshie8 (ganeshie8):
\(\large \frac{1}{x+1} = \frac{2}{x+3} \)
cross multiply
\(\large 1(x+3) = 2(x+1) \)
ganeshie8 (ganeshie8):
\(\large \frac{1}{x+1} = \frac{2}{x+3} \)
cross multiply
\(\large 1(x+3) = 2(x+1) \)
\(\large x+3 = 2x+ 2 \)
OpenStudy (anonymous):
i did, and i got ohhh wait
would it come out to be a fraction
???
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ganeshie8 (ganeshie8):
subtract x both sides
OpenStudy (anonymous):
okay, i got 5/3
ganeshie8 (ganeshie8):
\(\large x+3 = 2x+ 2 \)
-x -x
\(\large 3 = x+ 2 \)
ganeshie8 (ganeshie8):
subtract 2 both sides
OpenStudy (anonymous):
x=3
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OpenStudy (anonymous):
wait
OpenStudy (anonymous):
x=1
ganeshie8 (ganeshie8):
take ur time... its okay :)
ganeshie8 (ganeshie8):
Yes ! x = 1. Now verify if what we worked is correct or not
OpenStudy (anonymous):
okay,
so the answer options are
A.
x=5/3
B.
x = 1
C.
x = 5
D.
no solution
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ganeshie8 (ganeshie8):
you got x=1, so you tick that option
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