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Mathematics 19 Online
OpenStudy (anonymous):

solve and check

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

cross multiply

OpenStudy (anonymous):

then what? i dont know what my common denominator would be

OpenStudy (anonymous):

oh wait, x= 5?

ganeshie8 (ganeshie8):

try again

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

x=3

ganeshie8 (ganeshie8):

\(\large \frac{1}{x+1} = \frac{2}{x+3} \) cross multiply \(\large 1(x+3) = 2(x+1) \)

ganeshie8 (ganeshie8):

\(\large \frac{1}{x+1} = \frac{2}{x+3} \) cross multiply \(\large 1(x+3) = 2(x+1) \) \(\large x+3 = 2x+ 2 \)

OpenStudy (anonymous):

i did, and i got ohhh wait would it come out to be a fraction ???

ganeshie8 (ganeshie8):

subtract x both sides

OpenStudy (anonymous):

okay, i got 5/3

ganeshie8 (ganeshie8):

\(\large x+3 = 2x+ 2 \) -x -x \(\large 3 = x+ 2 \)

ganeshie8 (ganeshie8):

subtract 2 both sides

OpenStudy (anonymous):

x=3

OpenStudy (anonymous):

wait

OpenStudy (anonymous):

x=1

ganeshie8 (ganeshie8):

take ur time... its okay :)

ganeshie8 (ganeshie8):

Yes ! x = 1. Now verify if what we worked is correct or not

OpenStudy (anonymous):

okay, so the answer options are A. x=5/3 B. x = 1 C. x = 5 D. no solution

ganeshie8 (ganeshie8):

you got x=1, so you tick that option

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