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OpenStudy (anonymous):
what is x^3-x^2-6x in factored form?
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OpenStudy (espex):
With no integer, start by factoring an 'x' out of every term.
OpenStudy (anonymous):
x(x+2)(x-3)?
OpenStudy (espex):
Technically it is \(x[(x+2)(x-3)]\) but, yes. Good job.
OpenStudy (anonymous):
thanks
OpenStudy (espex):
You're welcome.
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