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Write the quadratic function with the following transformations: vertical shrink by 3, left 4, down 9
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\[f(x)=\frac{ 1 }{ 3 }(x-4)^{2}-9\]
should be x+4
yes,
ok
\[f(x)=\frac{ 1 }{ 3 }(x+4)^{2}-9\]
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f(x) = a(x - h)^2 + k a = width = vertical stretch h = horizontal shift k = vertical shift
@Jhannybean take a look https://www.boundless.com/algebra/graphs-functions-and-models/transformations/stretching-and-shrinking/
a between 0 and 1 is vertical shrink, so 1/3 is correct.
vertical shrink means parabola becomes wider.
Ah ok.i got it.
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