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factor: 2x^3+6x^2+x+3
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x = -3
\[(2x^{2}+1)(x+3)\]
how did you get there @etnoggin
sorry bout that.. i was wrong i didnt see the factor word LoL
Try watching this. https://www.khanacademy.org/math/algebra/quadratics/factoring_quadratics/v/factoring-trinomials-with-a-non-1-leading-coefficient-by-grouping
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(x + 3)(2x^2 + 1)
how did you get there @TjRoDz
try using foil method on either my equation or etnoggin's..
i did and it put it back into the original form, u
|dw:1372207067209:dw| hmm lets see (x)(2x^2) = 2x^3 (3)(1) = 3 (3)(2x^2) = 6x^2 (1)(x) = 1x or just x lemme combine 2x^3 + 3 + 6x^2 + x so it matches :)
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