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Which of the following is the solution of log (x + 5)0.001 = -3. (x+5)^-3=0.001. where would i go from here?
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note that \[0.001=10^{-3}\]
making \(x+5=10\)
how did you get to x+5=10
i could rewrite it as (x+5)^-3=10^-2? how do i get rid of the exponents though
\[(x+5)^{-3}=10^{-3}\iff x+5=10\]
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but one has an exponent of -3 and the other has -2? do do htye cancel?
\(0.001=10^{-3}\) not \(10^{-2}\) \[10^{-2}=0.01\]
oh i see thank you. that makes sense
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