A person spends 30% of his salary on house rent and 55% of the remaining money on food and clothes. Hesaves the remaining amount. If he saves ?59724 yearly, how much amount does he spend on food and clothes per month?

Question

shamim · Answer

let his salary is $$x$$

shamim · Answer

he spent for house rent and food, clothing is$$30+55=85$$

shamim · Answer

so his savings is$$100-85=15percent$$

shamim · Answer

so$$\frac{ 15 }{ 100 }x=59724$$

shamim · Answer

try to find $$x$$

shamim · Answer

his clothing cost wil b$$55 percent  \times x$$

shamim · Answer

$$\frac{ 55 }{ 100 }x$$

shamim · Answer

u need to divide this amount by 12

phi · Answer

I would interpret
**A person spends 30% of his salary on house rent and 55% of the remaining money on food and clothes.**
to mean

x = salary

0.3x  on rent   leaving 0.7x  remaining
0.55* 0.7 x on food and clothes

If he saves 59724 yearly,   you would say

x - (0.3x + 0.55*0.7x) = 59724

which says:  total salary minus expenses is saved, equal to 59724
you can solve this by simplifying.  first,  do 0.55*0.7:
x -  (0.3x + .385x) = 59724    
add 0.3x  and 0.385 x to get
x - 0.685x  = 59724

now simplify 1x -0.685 x  
0.315x  = 59724

divide both sides by 0.315  to get
x=  59724/0.315

anonymous · Answer

59724/12= 4977 (which is 15% of his monthly earnings)
so that multiplied by 2 is 9954:which is how much he spends of his house (30%)
then 4977/15*55= 18249:which is how much he spends on food and clothing (55%)

phi · Answer

to finish:  total salary for the year is 
x= 59724/0.315 = 189600

0.55* 0.7 * x on food and clothes per year, so
0.55*0.7*189600 =  72996 food and clothes per year

72996/12  = 6083  food and clothes per month