Can anyone help me with this?

Find the solution to the following problem in correct scientific notation:
(4.6 × 10^80) ÷ (2.3 × 10^40)

A. 2.0 × 10^2

B. 2.0 × 10^40

C. 2.0 × 10^80

D. 2.0 × 10^120

E. 2.0 × 10^3,200

Question

Can anyone help me with this? 


Find the solution to the following problem in correct scientific notation:
(4.6 × 10^80) ÷ (2.3 × 10^40)

A. 2.0 × 10^2

B. 2.0 × 10^40

C. 2.0 × 10^80

D. 2.0 × 10^120

E. 2.0 × 10^3,200

mayankdevnani · Answer

first, find the value of :
$$\huge \frac{4.6 \times 10^{80}}{2.3 \times 10^{40}}$$

mayankdevnani · Answer

so what is the answer???   @RH

mayankdevnani · Answer

can i help you to find the answer of this fraction?  @RH

anonymous · Answer

Yes if you don't mind :(

mayankdevnani · Answer

okkk..
so answer is :
$$\huge 2.0 \times 10^{40}$$

mayankdevnani · Answer

here the proof of this answer: http://www.wolframalpha.com/input/?i=%7B+4.6+*+10+%5E+%7B+80+%7D+%7D+%2F+%7B+2.3+*+10+%5E+%7B+40+%7D+%7D

anonymous · Answer

Thank you!!! But I don't understand how to solve it... :(

mayankdevnani · Answer

okk... i will help you

anonymous · Answer

Thank you so much:(

mayankdevnani · Answer

suppose we have this value:
|dw:1372241139643:dw|
what is its decimal value

mayankdevnani · Answer

@RH   can you write its value in decimal?

anonymous · Answer

0.002

anonymous · Answer

right?

mayankdevnani · Answer

right

mayankdevnani · Answer

and when i change this :
|dw:1372241426730:dw|
is there any affect on this value?